Sulfur Dioxide Preparation
What volume of SO2 at STP is produced when 0.25 mol Na2SO3 reacts completely with dilute H2SO4?
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Solution
5.60 L
From the reaction Na2SO3 + H2SO4 -> Na2SO4 + H2O + SO2, 1 mol Na2SO3 gives 1 mol SO2. Therefore 0.25 mol Na2SO3 produces 0.25 mol SO2. At STP, 1 mol gas occupies 22.4 L, so volume = 0.25 x 22.4 = 5.60 L. The value is physically reasonable because quarter mole should give quarter of molar gas volume.
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About This Question
- Subject
- chemistry
- Chapter
- p-block elements
- Topic
- sulfur dioxide preparation
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
5.60 L
From the reaction Na2SO3 + H2SO4 -> Na2SO4 + H2O + SO2, 1 mol Na2SO3 gives 1 mol SO2. Therefore 0.25 mol Na2SO3 produces 0.25 mol SO2. At STP, 1 mol gas occupies 22.4 L, so volume = 0.25 x 22.4 = 5.60 L. The value is physically reasonable because quarter mole should give quarter of molar gas volume.
This medium difficulty chemistry question is from the chapter p-block elements, covering the topic of sulfur dioxide preparation. It appeared in the 2025 exam.
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