Stopping Potential And Frequency
In a graph of stopping potential plotted against the frequency of incident light for a given metal, a physics student examines what the slope of the straight line represents.
Select the correct option:
Solution
Planck's constant divided by the electronic charge
Combining Einstein's equation with the stopping potential relation, NCERT shows that eV0=hν−ϕ, which rearranges to V0=ehν−eϕ. This is the equation of a straight line when V0 is plotted against frequency ν, with slope eh and a negative intercept eϕ on the vertical axis. Remarkably, the slope eh is the same for all metals, a striking confirmation of Einstein's theory that Millikan verified experimentally. The option naming the work function is wrong because the work function appears in the intercept, not the slope. The option naming the threshold frequency is wrong because the threshold frequency is the horizontal-axis intercept where V0=0, not the slope. The option giving the product h×e is wrong because dimensional analysis requires the slope to be eh, a ratio, so that volts result when multiplied by frequency. As stated in NCERT Class 12, Chapter 11, the universal slope of these lines allowed an accurate determination of Planck's constant. This linear graph is one of the most elegant confirmations of quantum theory, because both the universal slope and the metal-specific intercept can be read off a single straight line. The intercept on the frequency axis, where the stopping potential is zero, directly gives the threshold frequency of that particular metal, tying the whole picture together. A dimensional check confirms that eh carries units of volt-seconds, which multiplied by frequency in per-second yields volts, exactly matching the stopping potential.
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About This Question
- Subject
- physics
- Chapter
- dual nature of matter and radiation
- Topic
- stopping potential and frequency
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
Planck's constant divided by the electronic charge
Combining Einstein's equation with the stopping potential relation, NCERT shows that eV0=hν−ϕ, which rearranges to V0=ehν−eϕ. This is the equation of a straight line when V0 is plotted against frequency ν, with slope eh and a negative intercept eϕ on the vertical axis. Remarkably, the slope eh is the same for all metals, a striking confirmation of Einstein's theory that Millikan verified experimentally. The option naming the work function is wrong because the work function appears in the intercept, not the slope. The option naming the threshold frequency is wrong because the threshold frequency is the horizontal-axis intercept where V0=0, not the slope. The option giving the product h×e is wrong because dimensional analysis requires the slope to be eh, a ratio, so that volts result when multiplied by frequency. As stated in NCERT Class 12, Chapter 11, the universal slope of these lines allowed an accurate determination of Planck's constant. This linear graph is one of the most elegant confirmations of quantum theory, because both the universal slope and the metal-specific intercept can be read off a single straight line. The intercept on the frequency axis, where the stopping potential is zero, directly gives the threshold frequency of that particular metal, tying the whole picture together. A dimensional check confirms that eh carries units of volt-seconds, which multiplied by frequency in per-second yields volts, exactly matching the stopping potential.
This hard difficulty physics question is from the chapter dual nature of matter and radiation, covering the topic of stopping potential and frequency. It appeared in the 2025 exam.
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