Standing Waves
For string fixed at both ends length L fundamental frequency has wavelength:
Select the correct option:
Solution
λ = 2L
For a string fixed at both ends, periodic waves reflect from the boundaries and superimpose.
- Boundary Condition: Both ends (x=0,x=L) must be nodes (zero amplitude).
- Fundamental (1st Harmonic): This is the simplest possible pattern with only one antinode in the middle.
- Calculation: The distance between two successive nodes is λ/2. For the fundamental, this distance is equal to the string length L. L=λ/2⟹λ=2L.
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About This Question
- Subject
- physics
- Chapter
- oscillations and waves
- Topic
- standing waves
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
λ = 2L
For a string fixed at both ends, periodic waves reflect from the boundaries and superimpose.
- Boundary Condition: Both ends (x=0,x=L) must be nodes (zero amplitude).
- Fundamental (1st Harmonic): This is the simplest possible pattern with only one antinode in the middle.
- Calculation: The distance between two successive nodes is λ/2. For the fundamental, this distance is equal to the string length L. L=λ/2⟹λ=2L.
This medium difficulty physics question is from the chapter oscillations and waves, covering the topic of standing waves. It appeared in the 2025 exam.
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