Specific Heats And Gamma
Molar specific heat at constant volume for an ideal diatomic gas at room temperature, using the equipartition principle, takes which of the following values?
Select the correct option:
Solution
Five-halves of the universal gas constant R
Deriving this capacity combines equipartition with the definition of internal energy from NCERT Class 11, Chapter 13 (Kinetic Theory). A diatomic gas at room temperature has five degrees of freedom, three translational and two rotational, so by equipartition each mole stores internal energy U=25RT. Since the molar heat capacity at constant volume is CV=dTdU, differentiating gives CV=25R. The option 23R applies to a monatomic gas with only three translational degrees. The option 27R would apply only if vibrational modes were excited, which does not occur at ordinary room temperature. The option equal to R is far too small and matches no physical gas. The reason vibrational modes stay dormant is that they require far larger energy quanta to activate, so at room temperature only translation and rotation contribute to the heat capacity. A consistency check ties this to the specific heat ratio: with CV=25R and CP=CV+R=27R, the ratio γ=57=1.4, precisely the measured value for common diatomic gases such as nitrogen and oxygen, confirming the result.
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About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- specific heats and gamma
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Five-halves of the universal gas constant R
Deriving this capacity combines equipartition with the definition of internal energy from NCERT Class 11, Chapter 13 (Kinetic Theory). A diatomic gas at room temperature has five degrees of freedom, three translational and two rotational, so by equipartition each mole stores internal energy U=25RT. Since the molar heat capacity at constant volume is CV=dTdU, differentiating gives CV=25R. The option 23R applies to a monatomic gas with only three translational degrees. The option 27R would apply only if vibrational modes were excited, which does not occur at ordinary room temperature. The option equal to R is far too small and matches no physical gas. The reason vibrational modes stay dormant is that they require far larger energy quanta to activate, so at room temperature only translation and rotation contribute to the heat capacity. A consistency check ties this to the specific heat ratio: with CV=25R and CP=CV+R=27R, the ratio γ=57=1.4, precisely the measured value for common diatomic gases such as nitrogen and oxygen, confirming the result.
This medium difficulty physics question is from the chapter kinetic theory of gases, covering the topic of specific heats and gamma. It appeared in the 2025 exam.
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