Solubility Product
Mediumchemistry
The solubility product of AgCl at 298 K is 1.0 × 10⁻¹⁰. The solubility of AgCl in water is:
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Solution
Incorrect! Answer:
10⁻⁵ M
Silver chloride (AgCl) is a sparingly soluble salt. AgCl(s)⇌Ag+(aq)+Cl−(aq) If the solubility of AgCl is 's' mol/L, then:
- [Ag+]=s
- [Cl−]=s The Solubility Product Constant (Ksp) is: Ksp=[Ag+][Cl−]=s×s=s2 Given Ksp=1.0×10−10: s2=10−10⟹s=10−10=10−5 M
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About This Question
- Subject
- chemistry
- Chapter
- equilibrium
- Topic
- solubility product
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
10⁻⁵ M
Silver chloride (AgCl) is a sparingly soluble salt. AgCl(s)⇌Ag+(aq)+Cl−(aq) If the solubility of AgCl is 's' mol/L, then:
- [Ag+]=s
- [Cl−]=s The Solubility Product Constant (Ksp) is: Ksp=[Ag+][Cl−]=s×s=s2 Given Ksp=1.0×10−10: s2=10−10⟹s=10−10=10−5 M
This medium difficulty chemistry question is from the chapter equilibrium, covering the topic of solubility product. It appeared in the 2025 exam.
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