Sn1 Vs Sn2
Which substrate reacts fastest via SN1 in aqueous ethanol?
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More halogen organics Practice Questions
Chloroform stored with ethanol forms phosgene slowly; ethanol is added to:
Chloroform stored with ethanol forms phosgene slowly; ethanol is added to:
Strong bulky base (t-BuOK) acting on 2-bromobutane favors formation of:
Strong bulky base (t-BuOK) acting on 2-bromobutane favors formation of:
SN2 rate decreases in order:
SN2 rate decreases in order:
2-Bromobutane undergoes SN1 to give racemic mixture because:
2-Bromobutane undergoes SN1 to give racemic mixture because:
Finkelstein reaction converts R–Cl to R–I using NaI in acetone because:
Finkelstein reaction converts R–Cl to R–I using NaI in acetone because:
Elimination-addition (benzyne) mechanism is favored by treatment of chlorobenzene with:
Elimination-addition (benzyne) mechanism is favored by treatment of chlorobenzene with:
Formation of Grignard reagent fails in presence of:
Formation of Grignard reagent fails in presence of:
Wurtz reaction is less suitable for synthesis of unsymmetrical alkanes because:
Wurtz reaction is less suitable for synthesis of unsymmetrical alkanes because:
Sandmeyer reaction converts anilines to aryl bromides via intermediate:
Sandmeyer reaction converts anilines to aryl bromides via intermediate:
Best leaving group among given (in SN1):
Best leaving group among given (in SN1):
Chlorobenzene is less reactive than alkyl chloride in nucleophilic substitution because:
Chlorobenzene is less reactive than alkyl chloride in nucleophilic substitution because:
Benzylic bromides undergo SN1 faster than alkyl bromides due to:
Benzylic bromides undergo SN1 faster than alkyl bromides due to:
About This Question
- Subject
- chemistry
- Chapter
- halogen organics
- Topic
- sn1 vs sn2
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
(CH3)3CCl
- SN1 Mechanism: The rate-determining step is the formation of a carbocation intermediate.
- Rate Dependency: The stability of the carbocation directly determines the reaction rate. Stability order: Tertiary (3∘) > Secondary (2∘) > Primary (1∘) > Methyl.
- Analysis of Substrates:
- (CH3)3CCl (tert-butyl chloride): Forms a tertiary carbocation, (CH3)3C+, stabilized by 9 hyperconjugative H-atoms and +I effect of three methyl groups.
- CH3CH2Cl and CH3CH2CH2Cl: Form primary carbocations.
- CH3Cl: Forms a methyl carbocation (least stable).
- Conclusion: Tert-butyl chloride reacts fastest due to its superior carbocation stability.
This easy difficulty chemistry question is from the chapter halogen organics, covering the topic of sn1 vs sn2. It appeared in the 2025 exam.
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