Slope Of Stopping Potential Versus Frequency Graph
Two different metals are each tested in a photocell, and for both the stopping potential is plotted against the frequency of incident light. What can be correctly said about the slopes of the two straight-line graphs obtained?
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Solution
Bothslopesequalh/eandareidenticalforthetwometals
Writing Einstein's equation as a stopping-potential relation, eV0=hν−ϕ0, and dividing by e gives V0=ehν−eϕ0. This is a straight line in the variables V0 and ν, with slope eh and intercept −eϕ0 on the potential axis. The slope contains only the universal constants h and e, so it is exactly the same for every photosensitive material; only the intercept and the threshold frequency shift with work function. Hence the two graphs are parallel lines. The claim that a larger work function gives a steeper slope is wrong, because work function affects only the intercept. Equating the slope to the work function is dimensionally incorrect. The slope cannot depend on intensity, which influences only the saturation current. Millikan exploited exactly this universal slope to measure Planck's constant, a landmark experiment described in NCERT. As a check, the parallel-line prediction has been confirmed for many metals, strongly supporting the photon hypothesis over classical wave theory. A further insight is that extrapolating each parallel line back to zero stopping potential reveals that metal's threshold frequency on the horizontal axis, while the negative vertical intercept measures its work function divided by the charge. Thus a single linear graph encodes three quantities at once: the universal slope giving Planck's constant, and the two metal-specific intercepts giving the threshold and the work function.
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About This Question
- Subject
- physics
- Chapter
- dual nature of radiation and matter
- Topic
- slope of stopping potential versus frequency graph
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Bothslopesequalh/eandareidenticalforthetwometals
Writing Einstein's equation as a stopping-potential relation, eV0=hν−ϕ0, and dividing by e gives V0=ehν−eϕ0. This is a straight line in the variables V0 and ν, with slope eh and intercept −eϕ0 on the potential axis. The slope contains only the universal constants h and e, so it is exactly the same for every photosensitive material; only the intercept and the threshold frequency shift with work function. Hence the two graphs are parallel lines. The claim that a larger work function gives a steeper slope is wrong, because work function affects only the intercept. Equating the slope to the work function is dimensionally incorrect. The slope cannot depend on intensity, which influences only the saturation current. Millikan exploited exactly this universal slope to measure Planck's constant, a landmark experiment described in NCERT. As a check, the parallel-line prediction has been confirmed for many metals, strongly supporting the photon hypothesis over classical wave theory. A further insight is that extrapolating each parallel line back to zero stopping potential reveals that metal's threshold frequency on the horizontal axis, while the negative vertical intercept measures its work function divided by the charge. Thus a single linear graph encodes three quantities at once: the universal slope giving Planck's constant, and the two metal-specific intercepts giving the threshold and the work function.
This medium difficulty physics question is from the chapter dual nature of radiation and matter, covering the topic of slope of stopping potential versus frequency graph. It appeared in the 2025 exam.
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