Simple Pendulum
A grandfather clock keeps time using a simple pendulum, and its bob swings with a period of exactly 2 s at a place where g equals 9.8 m per second squared. What is the approximate length of this pendulum?
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About This Question
- Subject
- physics
- Chapter
- oscillations and waves
- Topic
- simple pendulum
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.99 m
A simple pendulum oscillating through small angles behaves as an SHM system with period T=2πL/g, where L is the length and g is the gravitational acceleration. The restoring agent here is the tangential component of gravity, which for small angles is proportional to displacement. Solving for length gives L=4π2gT2. Substituting T=2 s and g=9.8 m/s2, we get L=4π29.8×4=39.4839.2≈0.99 m. The value 0.50 m wrongly uses T=1 s or halves the result. The value 2.00 m simply copies the period as if it were a length, which is dimensionally invalid. The value 1.96 m omits the 4π2 denominator and instead divides only by 4. This is the classic seconds-pendulum result discussed in NCERT oscillations. As a plausibility check, a seconds pendulum is historically known to be about one metre long, confirming that 0.99 m is the physically expected answer.
This easy difficulty physics question is from the chapter oscillations and waves, covering the topic of simple pendulum. It appeared in the 2025 exam.
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