Section Formula In Three Dimensions
A point divides the segment joining (2, -1, 3) and (4, 3, -1) internally in the ratio 1:3, so find that point.
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About This Question
- Subject
- mathematics
- Chapter
- three dimensional geometry
- Topic
- section formula in three dimensions
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
(5/2,0,2)
The technique is the three-dimensional section formula: a point dividing the join of (x_1, y_1, z_1) and (x_2, y_2, z_2) internally in ratio m:n has coordinates ((m x_2 + n x_1)/(m+n), (m y_2 + n y_1)/(m+n), (m z_2 + n z_1)/(m+n)). This weighted-average formula is a core JEE Advanced result. With m:n = 1:3, m + n = 4, and endpoints (2, -1, 3) and (4, 3, -1): x = (1\cdot4 + 3\cdot2)/4 = (4 + 6)/4 = 10/4 = 5/2; y = (1\cdot3 + 3\cdot(-1))/4 = (3 - 3)/4 = 0; z = (1\cdot(-1) + 3\cdot3)/4 = (-1 + 9)/4 = 8/4 = 2. So the point is (5/2, 0, 2). Option (3, 1, 1) is the midpoint, ratio 1:1. Option (7/2, 2, 0) uses ratio 3:1, swapping m and n. Option (2/3, -1/3, 1) divides by the wrong total. This applies the internal section-formula theorem. Plausibility check: the point lies between the two endpoints since each coordinate falls within the corresponding endpoint range, consistent with internal division.
This easy difficulty mathematics question is from the chapter three dimensional geometry, covering the topic of section formula in three dimensions. It appeared in the 2025 exam.
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