Second Order Reaction
For a second-order reaction with equal initial concentrations of reactants, the half-life is:
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About This Question
- Subject
- chemistry
- Chapter
- chemical kinetics
- Topic
- second order reaction
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Inversely proportional to initial concentration
For a reaction 2A→Products following Second-Order Kinetics, the integrated rate law is: [A]t1=[A]01+kt At half-life (t=t1/2), [A]t=2[A]0. Substituting this into the equation: [A]0/21=[A]01+kt1/2 [A]02−[A]01=kt1/2 t1/2=k[A]01
- Thus, the half-life is inversely proportional to the initial concentration. This distinguishes it from first-order reactions where t1/2 is independent of concentration.
This medium difficulty chemistry question is from the chapter chemical kinetics, covering the topic of second order reaction. It appeared in the 2025 exam.
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