For an object rolling without slipping, the total kinetic energy ($K_{total}$) is the sum of:

1. Translational KE of the center of mass: $K_{trans}=\frac{1}{2}m{v}^2$.
2. Rotational KE about the center of mass: $K_{rot}=\frac{1}{2}I{\omega }^2$. $K_{total}=\frac{1}{2}m{v}^2+\frac{1}{2}I{\omega }^2$ Using $v=r\omega$, we can also write $K_{total}=\frac{1}{2}m{v}^2(1+\frac{k^2}{r^2})$ where $k$ is the radius of gyration.