Rms Speed
Consider a tank of nitrogen molecules each of molar mass 28 grams per mole maintained at 300 K, so what is the approximate root mean square speed of these molecules?
Select the correct option:
Solution
About517m/s
Determining molecular speed relies on the root mean square speed formula from NCERT Class 11, Chapter 13 (Kinetic Theory), written as vrms=M3RT, where R is the universal gas constant, T the absolute temperature and M the molar mass in kilograms per mole. Converting the molar mass gives M=28×10−3 kg/mol, and using R=8.314 J/(mol K) with T=300 K, the numerator 3RT=3×8.314×300=7482.6. Dividing by 0.028 gives 267236, and the square root is approximately 517 m/s. The option 300 m/s numerically echoes the temperature but has no physical basis. The option 1034 m/s is exactly double the correct value, arising from forgetting the square root and doubling instead. The option 173 m/s comes from dropping the factor of three in the formula. The rms speed itself is defined as the square root of the average of the squares of molecular speeds, a quantity that appears naturally in the kinetic pressure derivation. A magnitude check confirms the answer: gas molecular speeds at room temperature are typically several hundred metres per second, comparable to the speed of sound in the gas, so 517 m/s is entirely reasonable for nitrogen.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More rms speed Practice Questions
About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- rms speed
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
About517m/s
Determining molecular speed relies on the root mean square speed formula from NCERT Class 11, Chapter 13 (Kinetic Theory), written as vrms=M3RT, where R is the universal gas constant, T the absolute temperature and M the molar mass in kilograms per mole. Converting the molar mass gives M=28×10−3 kg/mol, and using R=8.314 J/(mol K) with T=300 K, the numerator 3RT=3×8.314×300=7482.6. Dividing by 0.028 gives 267236, and the square root is approximately 517 m/s. The option 300 m/s numerically echoes the temperature but has no physical basis. The option 1034 m/s is exactly double the correct value, arising from forgetting the square root and doubling instead. The option 173 m/s comes from dropping the factor of three in the formula. The rms speed itself is defined as the square root of the average of the squares of molecular speeds, a quantity that appears naturally in the kinetic pressure derivation. A magnitude check confirms the answer: gas molecular speeds at room temperature are typically several hundred metres per second, comparable to the speed of sound in the gas, so 517 m/s is entirely reasonable for nitrogen.
This medium difficulty physics question is from the chapter kinetic theory of gases, covering the topic of rms speed. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse kinetic theory of gases questions on RankGuru.