Resolving Power And Diffraction Limit
A telescope objective with a circular aperture of diameter 10 cm collects light of wavelength 500 nm from two distant stars. According to the Rayleigh criterion, what is the smallest angular separation the telescope can just resolve?
Select the correct option:
Solution
6.1×10−6rad
The Rayleigh criterion sets the diffraction limit on resolution for a circular aperture: two point sources are just resolved when the central maximum of one falls on the first diffraction minimum of the other, giving minimum angular separation θmin=D1.22λ, where λ is the wavelength and D the aperture diameter. Substituting λ=500×10−9 m and D=0.1 m yields θmin=0.11.22×500×10−9=0.16.1×10−7=6.1×10−6 rad. The factor 1.22 is not arbitrary—it emerges from the first zero of the Bessel function describing diffraction by a circular aperture, replacing the simple λ/a that applies to a rectangular slit. Resolution improves (the resolvable angle shrinks) either by using shorter wavelengths or by enlarging the aperture, which is the central reason astronomers build ever-larger primary mirrors and why ultraviolet or X-ray instruments can resolve finer structure than visible-light ones. The value 5.0×10−6 rad is wrong because it omits the 1.22 circular-aperture factor. The value 1.22×10−6 rad is wrong as it drops the wavelength scaling. The value 6.1×10−5 rad is wrong due to a misplaced power of ten in the aperture conversion. This NCERT limit explains why larger telescopes resolve finer detail. A check confirms a bigger aperture lowers θmin, so the micro-radian result is sensible for a 10 cm lens.
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About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- resolving power and diffraction limit
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
6.1×10−6rad
The Rayleigh criterion sets the diffraction limit on resolution for a circular aperture: two point sources are just resolved when the central maximum of one falls on the first diffraction minimum of the other, giving minimum angular separation θmin=D1.22λ, where λ is the wavelength and D the aperture diameter. Substituting λ=500×10−9 m and D=0.1 m yields θmin=0.11.22×500×10−9=0.16.1×10−7=6.1×10−6 rad. The factor 1.22 is not arbitrary—it emerges from the first zero of the Bessel function describing diffraction by a circular aperture, replacing the simple λ/a that applies to a rectangular slit. Resolution improves (the resolvable angle shrinks) either by using shorter wavelengths or by enlarging the aperture, which is the central reason astronomers build ever-larger primary mirrors and why ultraviolet or X-ray instruments can resolve finer structure than visible-light ones. The value 5.0×10−6 rad is wrong because it omits the 1.22 circular-aperture factor. The value 1.22×10−6 rad is wrong as it drops the wavelength scaling. The value 6.1×10−5 rad is wrong due to a misplaced power of ten in the aperture conversion. This NCERT limit explains why larger telescopes resolve finer detail. A check confirms a bigger aperture lowers θmin, so the micro-radian result is sensible for a 10 cm lens.
This hard difficulty physics question is from the chapter optics, covering the topic of resolving power and diffraction limit. It appeared in the 2025 exam.
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