Resistor Colour Code
A carbon resistor carries coloured bands in the sequence yellow, violet, orange, and gold. What is its resistance together with the stated tolerance?
Select the correct option:
Solution
47 k\(\Omega\) \(\pm\) 5%
The colour code on a carbon resistor encodes its value: the first two bands give significant figures, the third band is a power-of-ten multiplier, and the fourth band gives tolerance, following the standard sequence where yellow = 4, violet = 7, orange = 3 (multiplier (10^3)), and gold = (\pm)5%. Reading the bands, the significant figures are 4 and 7, forming 47, and the multiplier (10^3) scales this to (47 \times 10^3 = 47,000;\Omega = 47) k(\Omega), with a tolerance of (\pm)5%. The option 47 k(\Omega) (\pm)10% wrongly reads the gold band as silver. The option 4.7 k(\Omega) (\pm)5% uses a multiplier of (10^2), misreading orange. The option 470 k(\Omega) (\pm)5% overstates the multiplier as (10^4). This follows the NCERT carbon-resistor colour-code convention. A plausibility check confirms the reading: orange firmly denotes (10^3), so a 47 base value must land at 47 k(\Omega), and the gold band reliably fixes the tolerance at (\pm)5%.
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About This Question
- Subject
- physics
- Chapter
- current electricity
- Topic
- resistor colour code
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
47 k\(\Omega\) \(\pm\) 5%
The colour code on a carbon resistor encodes its value: the first two bands give significant figures, the third band is a power-of-ten multiplier, and the fourth band gives tolerance, following the standard sequence where yellow = 4, violet = 7, orange = 3 (multiplier (10^3)), and gold = (\pm)5%. Reading the bands, the significant figures are 4 and 7, forming 47, and the multiplier (10^3) scales this to (47 \times 10^3 = 47,000;\Omega = 47) k(\Omega), with a tolerance of (\pm)5%. The option 47 k(\Omega) (\pm)10% wrongly reads the gold band as silver. The option 4.7 k(\Omega) (\pm)5% uses a multiplier of (10^2), misreading orange. The option 470 k(\Omega) (\pm)5% overstates the multiplier as (10^4). This follows the NCERT carbon-resistor colour-code convention. A plausibility check confirms the reading: orange firmly denotes (10^3), so a 47 base value must land at 47 k(\Omega), and the gold band reliably fixes the tolerance at (\pm)5%.
This easy difficulty physics question is from the chapter current electricity, covering the topic of resistor colour code. It appeared in the 2025 exam.
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