Relation Between Am, Gm And Hm
For two distinct positive numbers, their arithmetic mean is 10 and their geometric mean is 8; compute the corresponding harmonic mean of the same pair.
Select the correct option:
Solution
6.4
For two positive numbers the arithmetic, geometric, and harmonic means satisfy the identity GM^2 = AM × HM, a relation tested heavily at JEE Advanced. Rearranging gives HM = GM^2 / AM = 8^2 / 10 = 64/10 = 6.4. This also respects the ordering AM ≥ GM ≥ HM, since 10 ≥ 8 ≥ 6.4 holds for the distinct numbers in question. Option 8 wrongly equates HM with GM, which only happens when the numbers are equal. Option 9 averages AM and GM rather than using the multiplicative relation. Option 5 mistakenly divides AM by 2. Hence the harmonic mean is 6.4. The identity GM^2 = AM × HM means the geometric mean is itself the geometric mean of the other two means, so knowing any two of the three means immediately determines the third without ever recovering the original numbers, a shortcut JEE Advanced expects students to apply fluently. Plausibility check: solving for the numbers from AM = 10 and GM = 8 gives roots of t^2 - 20t + 64 = 0, namely 4 and 16, whose harmonic mean 2·4·16/(4+16) = 128/20 = 6.4, confirming the identity directly.
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About This Question
- Subject
- mathematics
- Chapter
- sequence and series
- Topic
- relation between am, gm and hm
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
6.4
For two positive numbers the arithmetic, geometric, and harmonic means satisfy the identity GM^2 = AM × HM, a relation tested heavily at JEE Advanced. Rearranging gives HM = GM^2 / AM = 8^2 / 10 = 64/10 = 6.4. This also respects the ordering AM ≥ GM ≥ HM, since 10 ≥ 8 ≥ 6.4 holds for the distinct numbers in question. Option 8 wrongly equates HM with GM, which only happens when the numbers are equal. Option 9 averages AM and GM rather than using the multiplicative relation. Option 5 mistakenly divides AM by 2. Hence the harmonic mean is 6.4. The identity GM^2 = AM × HM means the geometric mean is itself the geometric mean of the other two means, so knowing any two of the three means immediately determines the third without ever recovering the original numbers, a shortcut JEE Advanced expects students to apply fluently. Plausibility check: solving for the numbers from AM = 10 and GM = 8 gives roots of t^2 - 20t + 64 = 0, namely 4 and 16, whose harmonic mean 2·4·16/(4+16) = 128/20 = 6.4, confirming the identity directly.
This medium difficulty mathematics question is from the chapter sequence and series, covering the topic of relation between am, gm and hm. It appeared in the 2025 exam.
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