Refraction By Thin Lenses
A luminous candle stands 30 cm from a thin converging lens whose focal length is 20 cm. Find the distance from the lens at which a sharp real image of the candle flame is produced.
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About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- refraction by thin lenses
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
60 cm
Thin lenses obey the lens equation v1−u1=f1 in the Cartesian convention, where a converging lens has positive focal length. Here f=+20 cm and the real object gives u=−30 cm. Substituting, v1=f1+u1=201+−301=603−2=601, so v=+60 cm. The positive image distance confirms a real image formed 60 cm beyond the lens on the side opposite the candle, which can be caught on a screen. The value 12 cm is wrong because it would arise from adding reciprocals instead of using correct signs. The value 15 cm is wrong as it is half the object distance with no physical basis here. The value 50 cm is wrong since it incorrectly sums object distance and focal length. This is the NCERT thin-lens result for an object beyond 2f... here between f and 2f, giving a magnified real image. A magnitude check confirms v>u, consistent with an enlarged real image.
This easy difficulty physics question is from the chapter optics, covering the topic of refraction by thin lenses. It appeared in the 2025 exam.
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