Refraction At A Plane Surface
A ray of light travelling through air strikes the smooth surface of a glass block of refractive index 1.5 at an angle of incidence of 60 degrees. Find the angle of refraction inside the glass.
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Solution
35.3°
Refraction at a plane boundary is governed by Snell's law, n1sinθ1=n2sinθ2, where the ray bends toward the normal on entering a denser medium. With air n1=1, glass n2=1.5 and incidence θ1=60°, we solve sinθ2=n2n1sinθ1=1.51×sin60°=1.50.866=0.577. Hence θ2=sin−1(0.577)≈35.3°, smaller than the incidence angle as expected for light entering glass. The bending occurs because light slows on entering the optically denser medium, and to keep the wavefronts continuous across the boundary the portion of each wavefront that enters first lags behind, swinging the ray toward the normal. The refractive index is precisely the ratio of the speed of light in vacuum to that in the medium, so a larger index means a greater slowing and a sharper bend. The value 30° is wrong because it would require sinθ2=0.5, corresponding to a different index. The value 41.8° is wrong as it is the critical angle for glass, relevant only for light leaving the glass. The value 60° is wrong since it simply repeats the incidence angle, implying no bending. This is the standard NCERT application of Snell's law at a single interface. A direction check confirms the refracted ray bends toward the normal, consistent with entry into a denser medium.
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About This Question
- Subject
- physics
- Chapter
- optics
- Topic
- refraction at a plane surface
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
35.3°
Refraction at a plane boundary is governed by Snell's law, n1sinθ1=n2sinθ2, where the ray bends toward the normal on entering a denser medium. With air n1=1, glass n2=1.5 and incidence θ1=60°, we solve sinθ2=n2n1sinθ1=1.51×sin60°=1.50.866=0.577. Hence θ2=sin−1(0.577)≈35.3°, smaller than the incidence angle as expected for light entering glass. The bending occurs because light slows on entering the optically denser medium, and to keep the wavefronts continuous across the boundary the portion of each wavefront that enters first lags behind, swinging the ray toward the normal. The refractive index is precisely the ratio of the speed of light in vacuum to that in the medium, so a larger index means a greater slowing and a sharper bend. The value 30° is wrong because it would require sinθ2=0.5, corresponding to a different index. The value 41.8° is wrong as it is the critical angle for glass, relevant only for light leaving the glass. The value 60° is wrong since it simply repeats the incidence angle, implying no bending. This is the standard NCERT application of Snell's law at a single interface. A direction check confirms the refracted ray bends toward the normal, consistent with entry into a denser medium.
This easy difficulty physics question is from the chapter optics, covering the topic of refraction at a plane surface. It appeared in the 2025 exam.
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