Rate Of Reaction
For the reaction 2N₂O₅(g) → 4NO₂(g) + O₂(g), if the rate of disappearance of N₂O₅ is 0.02 mol L⁻¹ s⁻¹, the rate of formation of NO₂ is:
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Solution
0.04 mol L⁻¹ s⁻¹
The rate of reaction is expressed as: Rate = −(1/2) d[N₂O₅]/dt = (1/4) d[NO₂]/dt. Therefore, d[NO₂]/dt = 2 × (−d[N₂O₅]/dt) = 2 × 0.02 = 0.04 mol L⁻¹ s⁻¹. The stoichiometric coefficients from the balanced equation determine the relative rates of consumption and formation of each species.
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About This Question
- Subject
- chemistry
- Chapter
- chemical kinetics
- Topic
- rate of reaction
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.04 mol L⁻¹ s⁻¹
The rate of reaction is expressed as: Rate = −(1/2) d[N₂O₅]/dt = (1/4) d[NO₂]/dt. Therefore, d[NO₂]/dt = 2 × (−d[N₂O₅]/dt) = 2 × 0.02 = 0.04 mol L⁻¹ s⁻¹. The stoichiometric coefficients from the balanced equation determine the relative rates of consumption and formation of each species.
This easy difficulty chemistry question is from the chapter chemical kinetics, covering the topic of rate of reaction. It appeared in the 2025 exam.
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