Range Of Projectile
For a given initial velocity of projection, the range is maximum when the angle of projection is:
Select the correct option:
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About This Question
- Subject
- physics
- Chapter
- kinematics
- Topic
- range of projectile
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
45°
- Range Formula: R=gu2sin(2θ).
- Analysis: For R to be maximum, the term sin(2θ) must be at its maximum value.
- Trigonometry: The maximum value of sin(x) is 1, which occurs when x=90∘.
- Solve for θ:
- 2θ=90∘⟹θ=45∘.
- Complementary Angles: Note that angles θ and 90∘−θ give the same range, but 45∘ stands unique as the peak for horizontal distance.
This easy difficulty physics question is from the chapter kinematics, covering the topic of range of projectile. It appeared in the 2025 exam.
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