Radioactive Decay Kinetics
Radioactive decay obeys first order kinetics; if a sample has a half-life of 5 years, what percentage remains after 15 years approximately?
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About This Question
- Subject
- chemistry
- Chapter
- chemical kinetics
- Topic
- radioactive decay kinetics
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
12.5 percent
Radioactive decay follows first order kinetics, so the half-life is constant and each half-life reduces the remaining sample to half of its previous amount. The number of half-lives in 15 years is 15/5 = 3. After each half-life the surviving fraction is multiplied by one-half, so after three half-lives the fraction remaining is (1/2)^3 = 1/8, which equals 12.5 percent of the original sample. The option 50 percent corresponds to one half-life only. The option 25 percent corresponds to two half-lives. The option 6.25 percent would require four half-lives, or 20 years. The first order nature of nuclear decay, with its characteristic constant half-life, is highlighted in NCERT kinetics. Understanding radioactive decay kinetics in this way ties directly into the wider study of chemical kinetics, where the same reasoning recurs across many problems. Plausibility check: starting at 100 percent and halving three times gives 100 → 50 → 25 → 12.5 percent, confirming that 12.5 percent remains after 15 years.
This easy difficulty chemistry question is from the chapter chemical kinetics, covering the topic of radioactive decay kinetics. It appeared in the 2025 exam.
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