Propagation Of Errors (product)
If A = (2.00 ± 0.02) and B = (3.0 ± 0.1), relative error in product P = AB is approximately?
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About This Question
- Subject
- physics
- Chapter
- physics and measurement
- Topic
- propagation of errors (product)
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
≈4%
- Rule for Product Errors: For P=AB, the relative error in the product is the sum of the relative errors in the components: PΔP=AΔA+BΔB.
- Relative error in A: 2.000.02=0.01 (or 1%).
- Relative error in B: 3.00.1≈0.0333 (or 3.33%).
- Total Relative Error: 0.01+0.0333=0.0433.
- Percentage conversion: 0.0433×100%≈4.3%.
- Conclusion: The closest estimate is 4%.
This hard difficulty physics question is from the chapter physics and measurement, covering the topic of propagation of errors (product). It appeared in the 2025 exam.
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