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Projectile On An Inclined Plane

Hardphysics

A particle is projected with speed 20 m/s horizontally from the top of an incline that makes 30 degrees with the horizontal, directed down the slope. Taking g = 10 m/s^2, after what time does the particle strike the inclined surface?

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About This Question

Subject
physics
Chapter
kinematics
Topic
projectile on an inclined plane
Difficulty
Hard
Year
2025
Tags
projectile on inclineinclined plane geometryslope constrainthorizontal projectiontime of impact

Solution

Correct Answer:

Projectile motion onto an incline is best handled by writing the horizontal and vertical displacements separately and imposing the geometric constraint that the landing point must lie on the sloping surface. Taking the launch point as origin with measured horizontally and measured vertically downward, the horizontal displacement is and the vertical drop under gravity is . Because the incline descends at 30 degrees below the horizontal, any point on its surface satisfies , equating the ratio of vertical drop to horizontal run with the tangent of the slope angle. Substituting gives , which simplifies to , so . The option s halves the correct root by misplacing the factor of four from the displacement ratio. The option s ignores the launch speed entirely. The option 2 s assumes a 45-degree slope rather than 30 degrees. This is the standard JEE Advanced slope-constraint method for projectiles. As a check, a gentler 30-degree incline lets the particle travel farther before meeting the surface, so a flight time above two seconds is physically reasonable.

This hard difficulty physics question is from the chapter kinematics, covering the topic of projectile on an inclined plane. It appeared in the 2025 exam.

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