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Pressure-temperature Law

Mediumphysics

A rigid sealed cylinder holds a gas at 2.0 \times 10^5 Pa and 300 K; find the new pressure when the temperature is raised to 450 K at constant volume.

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About This Question

Subject
physics
Chapter
kinetic theory of gases
Topic
pressure-temperature law
Difficulty
Medium
Year
2025
Tags
Gay-Lussac's lawisochoric processpressure-temperatureideal gasconstant volume

Solution

Correct Answer:

At constant volume the pressure of a fixed amount of ideal gas is directly proportional to its absolute temperature, a result known as Gay-Lussac's law: . This follows from with and held fixed, and microscopically it reflects that hotter molecules strike the walls both harder and more frequently. Solving for the new pressure, Pa. The temperatures must be expressed in kelvin for the proportionality to hold correctly. The value Pa inverts the temperature ratio. The value Pa mistakenly multiplies by an incorrect ratio arising from a celsius-to-kelvin confusion. The value Pa wrongly adds a fixed increment rather than scaling proportionally. This is the NCERT pressure–temperature law for an isochoric process, derived directly from the ideal gas equation and important for understanding why sealed containers can burst when heated near a flame and why pressure cookers and aerosol cans carry temperature warnings. As a plausibility check, raising the temperature by 50 % (from 300 K to 450 K) should raise the pressure by the same 50 %, taking Pa to Pa, exactly matching our computed result.

This medium difficulty physics question is from the chapter kinetic theory of gases, covering the topic of pressure-temperature law. It appeared in the 2025 exam.

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