Pressure Formula Hard

Question

Pressure of ideal gas can be written P = (1/3) ρ v_rms^2. Here ρ is:

RankGuru · Accepted Answer

The fundamental pressure equation from KTG is:
$P = \frac{1}{3} \frac{N}{V} m v_{rms}^2$
where $N$ is total number of molecules, $m$ is mass of one molecule, and $V$ is volume.
- The term $\frac{N m}{V}$ represents the **Total Mass / Volume**, which is the **mass density** ($\rho$).
- Therefore, $P = \frac{1}{3} \rho v_{rms}^2$.

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Pressure Formula Hard

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