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Power Sets

Easymathematics

Consider a set S having exactly n elements; the number of subsets of S that contain at least two elements is given by which expression in terms of n?

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About This Question

Subject
mathematics
Chapter
sets, relations and functions
Topic
power sets
Difficulty
Easy
Year
2025
Tags
advanced-calculus-drillpower-setsubset-countingcomplementary-countingcardinality

Solution

Correct Answer:

The total number of subsets of an n-element set is 2^n, since each element is independently included or excluded, a core counting theorem for power sets. Subsets with fewer than two elements are the empty set (1 subset) and the singletons (n subsets). Subtracting these unwanted cases gives 2^n - n - 1 subsets containing at least two elements. This complementary counting approach is a recurring JEE Advanced strategy: count the total and remove forbidden configurations. Option 2^n - n forgets to remove the empty set. Option 2^n - 1 removes only the empty set, leaving all singletons incorrectly included. Option 2^(n-1) counts subsets of even size or half the power set, unrelated to this constraint. Hence the required count is 2^n - n - 1. Plausibility check: for n = 3 the formula gives 8 - 3 - 1 = 4, matching the explicit subsets {a,b},{b,c},{a,c},{a,b,c}, confirming correctness for a small concrete case.

This easy difficulty mathematics question is from the chapter sets, relations and functions, covering the topic of power sets. It appeared in the 2025 exam.

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