Power And Power Factor
An AC circuit draws an RMS current of 4 A from a 100 V RMS source while the phase angle between voltage and current is 60 degrees. What is the average power consumed by the circuit?
Select the correct option:
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More electromagnetic induction and alternating currents Practice Questions
In a purely capacitive alternating current circuit connected to an oscillating source, what is the a...
In a purely capacitive alternating current circuit connected to an oscillating source, what is the a...
An alternating current circuit draws an rms current of 5 amperes from a 200 volt rms supply, and the...
An alternating current circuit draws an rms current of 5 amperes from a 200 volt rms supply, and the...
When an alternating voltage is applied across a pure resistor, what is the phase relationship betwee...
When an alternating voltage is applied across a pure resistor, what is the phase relationship betwee...
A current of 4 amperes flows steadily through a coil having a self-inductance of 0.5 henry. How much...
A current of 4 amperes flows steadily through a coil having a self-inductance of 0.5 henry. How much...
A rectangular armature coil of an AC generator has 100 turns and area 0.05 square metres, rotating a...
A rectangular armature coil of an AC generator has 100 turns and area 0.05 square metres, rotating a...
A series circuit contains a resistor of 30 ohm and an inductor whose inductive reactance is 40 ohm, ...
A series circuit contains a resistor of 30 ohm and an inductor whose inductive reactance is 40 ohm, ...
In the design of transformer cores and electromagnetic braking systems, why are the metallic cores c...
In the design of transformer cores and electromagnetic braking systems, why are the metallic cores c...
A series LCR circuit at resonance has an inductive reactance of 500 ohm and a resistance of 25 ohm. ...
A series LCR circuit at resonance has an inductive reactance of 500 ohm and a resistance of 25 ohm. ...
A charged capacitor of 2 microfarads is connected across an ideal inductor of 8 millihenry to form a...
A charged capacitor of 2 microfarads is connected across an ideal inductor of 8 millihenry to form a...
The current flowing through a coil of self-inductance 0.6 henry is reduced steadily from 10 amperes ...
The current flowing through a coil of self-inductance 0.6 henry is reduced steadily from 10 amperes ...
In an AC circuit, a capacitor of capacitance 25 microfarads is connected to a source whose frequency...
In an AC circuit, a capacitor of capacitance 25 microfarads is connected to a source whose frequency...
A series LCR circuit contains an inductor of 2 henry and a capacitor of 8 microfarads along with a r...
A series LCR circuit contains an inductor of 2 henry and a capacitor of 8 microfarads along with a r...
Browse all electromagnetic induction and alternating currents questions →
About This Question
- Subject
- physics
- Chapter
- electromagnetic induction and alternating currents
- Topic
- power and power factor
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
200 W
Average power in an AC circuit is delivered only by the in-phase component of current, so it equals the product of RMS voltage, RMS current and the power factor (\cos\phi), giving (P_{avg} = V_{rms} I_{rms}\cos\phi). The reactive part of the current carries energy back and forth without net dissipation. Substituting (V_{rms} = 100) V, (I_{rms} = 4) A and (\cos 60^\circ = 0.5) yields (P_{avg} = 100 \times 4 \times 0.5 = 200) W. The option 400 W is the apparent power (V_{rms}I_{rms}), which ignores the phase factor. The option 100 W mistakenly applies (\cos\phi) twice. The option 346 W uses (\sin 60^\circ), which would give the wattless reactive power instead. This is the NCERT distinction between true, apparent and reactive power, where true power is measured in watts, apparent power in volt-amperes, and reactive power in volt-amperes reactive. Improving the power factor toward unity, for instance by adding a correcting capacitor to an inductive load, reduces the current needed to deliver the same useful power and so cuts transmission losses. A plausibility check confirms the true power must be smaller than the apparent power whenever a phase difference exists, and is exactly half here because the power factor is 0.5, consistent with a moderately reactive load drawing substantial wattless current.
This medium difficulty physics question is from the chapter electromagnetic induction and alternating currents, covering the topic of power and power factor. It appeared in the 2025 exam.
Looking for more practice? Explore all physics questions or browse electromagnetic induction and alternating currents questions on RankGuru.