Perpendicular Vectors
Find the scalar value m so that the vector 2i + m j + k becomes perpendicular to the vector i - 3j + 2k in space.
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About This Question
- Subject
- mathematics
- Chapter
- vector algebra
- Topic
- perpendicular vectors
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
4/3
Two vectors are perpendicular exactly when their dot product equals zero, since cos(90 degrees) = 0 forces the scalar product to vanish. Imposing the orthogonality condition and solving for the unknown is a frequent JEE Advanced parameter problem. Compute the dot product of (2, m, 1) and (1, -3, 2): (2)(1) + (m)(-3) + (1)(2) = 2 - 3m + 2 = 4 - 3m. Setting this equal to zero gives 4 - 3m = 0, so 3m = 4 and m = 4/3. Option 3/4 inverts the fraction by dividing incorrectly. Option -4/3 drops a sign when isolating m. Option 2 ignores the j-contribution entirely, solving only the constant terms. The positive value 4/3 is the unique scalar making the angle exactly 90 degrees. Geometrically, adjusting m tilts the first vector until its projection onto the second cancels to zero. Plausibility check: substituting m = 4/3 back gives 4 - 3(4/3) = 4 - 4 = 0, confirming the dot product vanishes and the vectors are indeed orthogonal.
This easy difficulty mathematics question is from the chapter vector algebra, covering the topic of perpendicular vectors. It appeared in the 2025 exam.
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