Skip to content

Perpendicular Axis Theorem

Mediumphysics

A thin square plate has a moment of inertia I about an axis lying in its plane and passing through its centre parallel to one edge. What is its moment of inertia about an axis perpendicular to the plate through the same centre?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

About This Question

Subject
physics
Chapter
rotational motion
Topic
perpendicular axis theorem
Difficulty
Medium
Year
2025
Tags
perpendicular axis theoremsquare plateplanar laminain-plane symmetrymoment of inertia

Solution

Correct Answer:

2I

The perpendicular axis theorem applies to flat planar laminae and states , where the -axis is perpendicular to the plate and the - and -axes lie in its plane through the same point. By the symmetry of a square plate, the in-plane moments of inertia about the two central axes parallel to its edges are equal, . Therefore . The value I forgets that two separate in-plane contributions must be summed. The value I/2 inverts the relationship between the perpendicular and in-plane axes. The value 4I wrongly squares the count of contributions instead of adding them. This is the NCERT perpendicular axis theorem, valid only for two-dimensional bodies of negligible thickness. As a consistency check, the perpendicular axis sees mass distributed in both planar directions at once, so its moment of inertia must be larger than either single in-plane value, and confirms this expectation cleanly. The theorem holds only for thin laminae because it assumes every mass element lies in the plane of the plate; for a thick three-dimensional block the mass spreads along the perpendicular axis itself and the simple sum no longer applies.

This medium difficulty physics question is from the chapter rotational motion, covering the topic of perpendicular axis theorem. It appeared in the 2025 exam.

Looking for more practice? Explore all physics questions or browse rotational motion questions on RankGuru.