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Oxidising Agent Identification

Easychemistry

Across a reaction where sulphur dioxide decolourises acidified potassium permanganate, which species behaves as the oxidising agent in the process?

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About This Question

Subject
chemistry
Chapter
redox reactions and electrochemistry
Topic
oxidising agent identification
Difficulty
Easy
Year
2025
Tags
oxidising agentpermanganate reductionsulphur dioxide oxidationacidic mediumcolour change

Solution

Correct Answer:

Potassium permanganate

An oxidising agent is the species that gains electrons and is itself reduced, causing oxidation of another substance. When sulphur dioxide reacts with acidified potassium permanganate, manganese is reduced from +7 in MnO_4^- to +2 in Mn^2+, while sulphur is oxidised from +4 in SO_2 to +6 in SO_4^2-. Because permanganate accepts electrons and brings about the oxidation of sulphur dioxide, potassium permanganate is the oxidising agent, and its characteristic purple colour fades as colourless Mn^2+ forms. Sulphur dioxide is incorrect because it loses electrons and is the reducing agent here. Water participates as a medium and proton source but undergoes no change in oxidation state. The potassium ion is a spectator that does not change oxidation number. This decolourisation is a standard NCERT test illustrating permanganate as a powerful oxidant in acidic medium. Plausibility check: the disappearance of the purple permanganate colour signals its reduction to Mn^2+, confirming it acted as the oxidising agent.

This easy difficulty chemistry question is from the chapter redox reactions and electrochemistry, covering the topic of oxidising agent identification. It appeared in the 2025 exam.

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