Oxidation Number

Question

The oxidation number of Cr in K₂Cr₂O₇ is:

RankGuru · Accepted Answer

To find the oxidation number of Chromium ($Cr$) in Potassium Dichromate ($K_2Cr_2O_7$):
- **Standard Values**: $K = +1$ (Group 1), $O = -2$ (typical).
- Let the oxidation number of $Cr$ be '$x$'.
- Total charge on the neutral molecule = $0$.
- Calculation: $2(+1) + 2(x) + 7(-2) = 0$
$2 + 2x - 14 = 0$
$2x = 12 \Rightarrow x = +6$
- Thus, each chromium atom in dichromate is in the $+6$ oxidation state.

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