Osmotic Pressure
A solution containing 0.5 g of a protein in 100 mL of solution has an osmotic pressure of 1.23 × 10⁻³ atm at 300 K. The molar mass of the protein is: (R = 0.082 L atm K⁻¹ mol⁻¹)
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About This Question
- Subject
- chemistry
- Chapter
- solutions
- Topic
- osmotic pressure
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
100000 g/mol
Osmotic Pressure (π) is defined by the formula: π=VnRT=MVwRT
- Given:
- π=1.23×10−3 atm
- w=0.5 g, V=100 mL=0.1 L
- R=0.082 L atm K−1 mol−1, T=300 K
- Calculation: M=πVwRT=1.23×10−3×0.10.5×0.082×300 M=1.23×10−412.3=105=100,000 g/mol.
This hard difficulty chemistry question is from the chapter solutions, covering the topic of osmotic pressure. It appeared in the 2025 exam.
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