Skip to content

Order Of Reaction

Easychemistry

If doubling the concentration of a reactant quadruples the reaction rate while other concentrations stay fixed, what is the order with respect to that reactant?

Select the correct option:

🔒 Solution Hidden from View

Submit your answer to unlock the detailed step-by-step solution.

About This Question

Subject
chemistry
Chapter
chemical kinetics
Topic
order of reaction
Difficulty
Easy
Year
2025
Tags
order of reactionrate lawconcentration dependenceexperimental ordersecond order

Solution

Correct Answer:

Second

The order with respect to a reactant is the power to which its concentration is raised in the experimentally determined rate law, and it can be found from how the rate responds to concentration changes. If rate ∝ [A]^x, then doubling [A] multiplies the rate by 2^x. Here the rate becomes four times larger, so 2^x = 4, which gives x = 2. The reaction is therefore second order with respect to that reactant. The zero-order option would leave the rate unchanged on doubling. First order would only double the rate. Third order would multiply the rate by eight. Order is an empirical quantity that need not match the stoichiometric coefficient, a key NCERT distinction between order and molecularity. Plausibility check: a fourfold rate increase corresponds exactly to squaring the doubled concentration, so second order is the only consistent value.

This easy difficulty chemistry question is from the chapter chemical kinetics, covering the topic of order of reaction. It appeared in the 2025 exam.

Looking for more practice? Explore all chemistry questions or browse chemical kinetics questions on RankGuru.