Ohm's Law
A nichrome heating element draws a steady current of 2.5 A when connected across a 220 V domestic supply. What is its operating resistance?
Select the correct option:
Solution
88 \(\Omega\)
Ohm's Law expresses that, for a conductor at constant temperature, the current flowing through it is directly proportional to the applied potential difference, so the ratio (V/I) defines a fixed resistance (R). For an ohmic device such as a nichrome element operating in steady state, this resistance is the meaningful conductive opposition the circuit experiences. Rearranging (V = IR) gives (R = V/I). Substituting the supply voltage (V = 220) V and the measured current (I = 2.5) A yields (R = 220/2.5 = 88;\Omega). The option 55 (\Omega) is incorrect because it would demand a current of 4 A, far above the stated value. The option 110 (\Omega) is wrong since it corresponds to a current of only 2 A. The option 220 (\Omega) is wrong because numerically equating resistance with voltage ignores the current entirely. This is the standard NCERT treatment of resistance as the constant of proportionality in Ohm's Law. A plausibility check confirms the answer: 88 (\Omega) carrying 2.5 A indeed dissipates about 550 W, a typical rating for a heating appliance.
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Ohm's law states current through a conductor is directly proportional to?
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A resistor of 10 Ω carries a current of 2 A. What is the potential difference across it?
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Ohm's law states V proportional to:
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About This Question
- Subject
- physics
- Chapter
- current electricity
- Topic
- ohm's law
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
88 \(\Omega\)
Ohm's Law expresses that, for a conductor at constant temperature, the current flowing through it is directly proportional to the applied potential difference, so the ratio (V/I) defines a fixed resistance (R). For an ohmic device such as a nichrome element operating in steady state, this resistance is the meaningful conductive opposition the circuit experiences. Rearranging (V = IR) gives (R = V/I). Substituting the supply voltage (V = 220) V and the measured current (I = 2.5) A yields (R = 220/2.5 = 88;\Omega). The option 55 (\Omega) is incorrect because it would demand a current of 4 A, far above the stated value. The option 110 (\Omega) is wrong since it corresponds to a current of only 2 A. The option 220 (\Omega) is wrong because numerically equating resistance with voltage ignores the current entirely. This is the standard NCERT treatment of resistance as the constant of proportionality in Ohm's Law. A plausibility check confirms the answer: 88 (\Omega) carrying 2.5 A indeed dissipates about 550 W, a typical rating for a heating appliance.
This easy difficulty physics question is from the chapter current electricity, covering the topic of ohm's law. It appeared in the 2025 exam.
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