Numerical: Species-area

Question

If a region shows a species-area relationship of S = 5A^0.25 (where S = number of species, A = area in km²), how many species are predicted in a 256 km² area?

RankGuru · Accepted Answer

1. **Formula**: $S = C \cdot A^z$, given as $S = 5 \cdot A^{0.25}$.
2. **Input Value**: $A = 256 \ km^2$.
3. **Calculation**:
   - $S = 5 	imes (256)^{0.25}$
   - Note that exponent $0.25$ is the same as the **fourth root** ($\sqrt[4]{A}$).
   - Fourth root of $256$: We know $4 	imes 4 = 16$, $16 	imes 4 = 64$, $64 	imes 4 = 256$. So, $\sqrt[4]{256} = 4$.
   - $S = 5 	imes 4 = \mathbf{20}$.
4. **Conclusion**: 20 species are predicted in this area.

Rank Guru

Numerical: Species-area

Select the correct option:

Solution

🔒 Solution Hidden from View

About This Question