Numerical: Epidemic Growth
Mediumbiology
An infection doubles its case count every 3 days. Starting with 400 cases, how many after 9 days assuming ideal doubling?
Select the correct option:
Solution
Incorrect! Answer:
3200
- Identify Number of Intervals:
- Total time = 9 days.
- Doubling time = 3 days.
- Number of doublings (n) = Doubling timeTotal time=39=3.
- Apply Growth Formula:
- Final count=Initial count×2n
- Final count=400×23=400×8=3200.
- Manual Check:
- Start: 400
- Day 3: 800
- Day 6: 1600
- Day 9: 3200.
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About This Question
- Subject
- biology
- Chapter
- biology and human welfare
- Topic
- numerical: epidemic growth
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
3200
- Identify Number of Intervals:
- Total time = 9 days.
- Doubling time = 3 days.
- Number of doublings (n) = Doubling timeTotal time=39=3.
- Apply Growth Formula:
- Final count=Initial count×2n
- Final count=400×23=400×8=3200.
- Manual Check:
- Start: 400
- Day 3: 800
- Day 6: 1600
- Day 9: 3200.
This medium difficulty biology question is from the chapter biology and human welfare, covering the topic of numerical: epidemic growth. It appeared in the 2025 exam.
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