Numerical: Bacterial Growth
Hardbiology
A bacterial culture in log phase doubles every 30 minutes. Starting with 5 x 10^3 cells, how many cells will be present after 2 hours assuming ideal conditions?
Select the correct option:
Solution
Incorrect! Answer:
8x104
- Calculate Number of Generations (n):
- Total time = 2 hours = 120 minutes.
- Generation (doubling) time = 30 minutes.
- n=30120=4 generations.
- Calculate Final Population:
- Final Population=Initial Population×2n
- Final Population=(5×103)×24=(5×103)×16
- Final Population=80×103=8×104.
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About This Question
- Subject
- biology
- Chapter
- diversity in living world
- Topic
- numerical: bacterial growth
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
8x104
- Calculate Number of Generations (n):
- Total time = 2 hours = 120 minutes.
- Generation (doubling) time = 30 minutes.
- n=30120=4 generations.
- Calculate Final Population:
- Final Population=Initial Population×2n
- Final Population=(5×103)×24=(5×103)×16
- Final Population=80×103=8×104.
This hard difficulty biology question is from the chapter diversity in living world, covering the topic of numerical: bacterial growth. It appeared in the 2025 exam.
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