Nitro Reduction

Question

Reduction of nitrobenzene with Sn/HCl gives initially:

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1. **Reductive Sequence**: Reduction of nitrobenzene involves multiple stages of electron and proton transfer.
2. **Path**: $C_6H_5NO_2 	o C_6H_5NO$ (Nitrosobenzene) $	o C_6H_5NHOH$ (**Phenylhydroxylamine**) $	o C_6H_5NH_2$ (**Aniline**).
3. **Conditions**: In an acidic medium with a strong reducing agent like $Sn/HCl$ or $Fe/HCl$, the reaction proceeds all the way to aniline.
4. **Note**: If the medium is neutral ($Zn/NH_4Cl$), the reaction stops at Phenylhydroxylamine.

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Nitro Reduction

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