Nitro Reduction
Reduction of nitrobenzene with Sn/HCl gives initially:
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More nitrogen organics Practice Questions
Diazotization of aniline performed at low temperature (~0–5°C) because:
Diazotization of aniline performed at low temperature (~0–5°C) because:
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Primary aliphatic amine treated with nitrous acid evolves:
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Replacement of diazonium with –OH occurs by heating aqueous solution yielding:
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Hofmann bromamide reaction converts an amide to:
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Formation of nitrosyl derivative (green coloration) with secondary amine indicates:
In Hinsberg test, secondary amine gives product that is:
In Hinsberg test, secondary amine gives product that is:
Treatment of benzenediazonium chloride with CuCN (Sandmeyer) yields:
Treatment of benzenediazonium chloride with CuCN (Sandmeyer) yields:
Gabriel phthalimide synthesis is used to prepare:
Gabriel phthalimide synthesis is used to prepare:
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Aniline is less basic than methylamine due to:
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Carbylamine test requires chloroform and alcoholic KOH; characteristic product is:
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About This Question
- Subject
- chemistry
- Chapter
- nitrogen organics
- Topic
- nitro reduction
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
Phenylhydroxylamine then aniline
- Reductive Sequence: Reduction of nitrobenzene involves multiple stages of electron and proton transfer.
- Path: C6H5NO2→C6H5NO (Nitrosobenzene) →C6H5NHOH (Phenylhydroxylamine) →C6H5NH2 (Aniline).
- Conditions: In an acidic medium with a strong reducing agent like Sn/HCl or Fe/HCl, the reaction proceeds all the way to aniline.
- Note: If the medium is neutral (Zn/NH4Cl), the reaction stops at Phenylhydroxylamine.
This hard difficulty chemistry question is from the chapter nitrogen organics, covering the topic of nitro reduction. It appeared in the 2025 exam.
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