Nitration Of Benzene

Nitrating Mixture: Concentrated $H N O_{3}$ and concentrated $H_{2} S O_{4}$ at $50 - 6 0^{\circ} C$ .
The Electrophile: The nitronium ion ( $N O_{2}^{+}$ ) is generated by the reaction: $H N O_{3} + 2 H_{2} S O_{4} \to N O_{2}^{+} + 2 H S O_{4}^{-} + H_{3} O^{+}$
The nitronium ion attacks the benzene ring to form the intermediate sigma-complex, ultimately resulting in Nitrobenzene ( $C_{6} H_{5} N O_{2}$ ).

This easy difficulty chemistry question is from the chapter hydrocarbons, covering the topic of nitration of benzene. It appeared in the 2025 exam.

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Nitration Of Benzene

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A hydrocarbon with the molecular formula $C_{6} H_{10}$ is being analysed, and the total number of degr...