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Newton's Second Law

Easyphysics

A hockey puck of mass 0.16 kg resting on smooth ice is struck so that it gains a steady acceleration of 25 m/s^2. What is the magnitude of the net force applied to the puck?

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About This Question

Subject
physics
Chapter
laws of motion
Topic
newton's second law
Difficulty
Easy
Year
2025
Tags
Newton's second lawforce and accelerationfrictionless surfacenet forceF equals ma

Solution

Correct Answer:

4 N

Newton's Second Law tells us that the net external force on a body equals the product of its mass and its acceleration, written as . On smooth ice the frictional resistance is negligible, so the striking force is essentially the entire net force responsible for the puck's acceleration. Substituting the given values, . The value 2 N corresponds to an acceleration of only 12.5 m/s^2, half the stated figure, so it is incorrect. The value 6 N would require an acceleration of 37.5 m/s^2, which exceeds what is given. The value 8 N would correspond to doubling the true mass or acceleration and therefore cannot match the data. This is a direct application of the NCERT formulation of the Second Law for a single body on a frictionless surface. As a unit check, kilogram times metre per second squared yields the newton, and the modest 4 N magnitude is reasonable for a light puck on slippery ice.

This easy difficulty physics question is from the chapter laws of motion, covering the topic of newton's second law. It appeared in the 2025 exam.

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