Nernst Equation
Nernst equation relates electrode potential to:
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For cell: Zn(s)|Zn²⁺(1 M)||Cu²⁺(1 M)|Cu(s), E°(Zn²⁺/Zn) = -0.76 V, E°(Cu²⁺/Cu) = +0.34 V. E°cell is:
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About This Question
- Subject
- chemistry
- Chapter
- electrochemistry
- Topic
- nernst equation
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Concentration (activity) of species
- The Equation: E=E∘−nFRTlnQ, where Q is the reaction quotient.
- Variable Q: Q is defined by the concentrations (or activities) of products divided by reactants.
- Application: It explains why the cell potential changes as reactants are consumed and products are formed. When the concentrations are non-standard (not 1 M), E=E∘.
- Equilibrium: As Q approaches the equilibrium constant K, E drops toward zero. At equilibrium, E=0.
This medium difficulty chemistry question is from the chapter electrochemistry, covering the topic of nernst equation. It appeared in the 2025 exam.
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