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Nature Of Roots

Easymathematics

For the quadratic equation 2x^2 - 7x + 6 = 0 with real coefficients, the discriminant analysis shows the roots have which character and form?

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About This Question

Subject
mathematics
Chapter
complex numbers and quadratic equations
Topic
nature of roots
Difficulty
Easy
Year
2025
Tags
advanced-calculus-drilldiscriminantnature-of-rootsrational-rootsquadratic-equation

Solution

Correct Answer:

Real, distinct and rational

The discriminant D = b^2 - 4ac determines the nature of the roots of a quadratic, the first tool applied in JEE Advanced root analysis. For 2x^2 - 7x + 6 = 0, we have a = 2, b = -7, c = 6, so D = 49 - 4·2·6 = 49 - 48 = 1. Since D > 0 the roots are real and distinct, and because D = 1 is a perfect square with rational coefficients, the roots are rational. Solving, x = (7 ± 1)/4 gives x = 2 and x = 3/2, both rational and unequal. Option real equal would require D = 0. Option complex conjugates would require D < 0. Option real distinct irrational would require D positive but not a perfect square. Hence the roots are real, distinct, and rational. Plausibility check: substituting x = 2 gives 8 - 14 + 6 = 0 and x = 3/2 gives 4.5 - 10.5 + 6 = 0, both satisfying the equation, confirming the rational distinct roots.

This easy difficulty mathematics question is from the chapter complex numbers and quadratic equations, covering the topic of nature of roots. It appeared in the 2025 exam.

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