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Motion Under Gravity

Easyphysics

A stone is dropped from the top of a tower and reaches the ground in 4 seconds, taking g equal to 10 m/s², what is the height of the tower?

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About This Question

Subject
physics
Chapter
kinematics
Topic
motion under gravity
Difficulty
Easy
Year
2025
Tags
free fallacceleration due to gravitydropped objectheight calculationkinematic equation

Solution

Correct Answer:

80 m

Following NCERT Class 11, Chapter 3 (Motion in a Straight Line), an object in free fall under gravity starts with zero initial velocity and accelerates downward at g. The height fallen is h = (1/2)gt². Here the stone is simply dropped, so u = 0, and substituting g = 10 m/s² with t = 4 s gives h = (1/2) × 10 × 16 = 80 m. The option 40 m wrongly drops the factor of one-half twice or uses t = 4 with g halved improperly. The option 160 m results from forgetting the one-half factor entirely (10 × 16 = 160). The option 20 m comes from using t = 2 s instead of the given 4 s. Plausibility check: the final velocity on impact would be gt = 40 m/s, and the average velocity over the fall is 20 m/s, which across 4 s yields 80 m, matching our result and confirming the calculation is dimensionally and numerically sound.

This easy difficulty physics question is from the chapter kinematics, covering the topic of motion under gravity. It appeared in the 2025 exam.

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