Molecular Formula

Question

A compound contains C=40%, H=6.7%, O=53.3%. The empirical formula is:

RankGuru · Accepted Answer

To find the **Empirical Formula**:
1. **Moles Calculation**:
- $C: 40/12.0 \approx 3.33 	ext{ mol}$
- $H: 6.7/1.0 = 6.7 	ext{ mol}$
- $O: 53.3/16.0 \approx 3.33 	ext{ mol}$
2. **Divide by Smallest**:
- $C: 3.33/3.33 = 1$
- $H: 6.7/3.33 \approx 2$
- $O: 3.33/3.33 = 1$
- **Relative Ratio**: $1 : 2 : 1$.
- Empirical Formula: **$CH_2O$**.

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A compound contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. Its empirical formula is:

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