Molecular Formula
A compound contains C=40%, H=6.7%, O=53.3%. The empirical formula is:
Select the correct option:
Solution
CH₂O
To find the Empirical Formula:
- Moles Calculation:
- C:40/12.0≈3.33 mol
- H:6.7/1.0=6.7 mol
- O:53.3/16.0≈3.33 mol
- Divide by Smallest:
- C:3.33/3.33=1
- H:6.7/3.33≈2
- O:3.33/3.33=1
- Relative Ratio: 1:2:1.
- Empirical Formula: CH2O.
🔒 Solution Hidden from View
Submit your answer to unlock the detailed step-by-step solution.
More molecular formula Practice Questions
A hydrocarbon contains 92.3% carbon by mass and has a molar mass of 78 g/mol. What is its molecular ...
A hydrocarbon contains 92.3% carbon by mass and has a molar mass of 78 g/mol. What is its molecular ...
An organic compound contains 40.0% carbon and 6.7% hydrogen with the remainder oxygen, and its molar...
An organic compound contains 40.0% carbon and 6.7% hydrogen with the remainder oxygen, and its molar...
A compound contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. Its empirical formula is:
A compound contains 40% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. Its empirical formula is:
About This Question
- Subject
- chemistry
- Chapter
- purification and characterisation of organic compounds
- Topic
- molecular formula
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
CH₂O
To find the Empirical Formula:
- Moles Calculation:
- C:40/12.0≈3.33 mol
- H:6.7/1.0=6.7 mol
- O:53.3/16.0≈3.33 mol
- Divide by Smallest:
- C:3.33/3.33=1
- H:6.7/3.33≈2
- O:3.33/3.33=1
- Relative Ratio: 1:2:1.
- Empirical Formula: CH2O.
This medium difficulty chemistry question is from the chapter purification and characterisation of organic compounds, covering the topic of molecular formula. It appeared in the 2025 exam.
Looking for more practice? Explore all chemistry questions or browse purification and characterisation of organic compounds questions on RankGuru.