Mole Fraction And Mass Fraction
A mixture contains 36 g of water and 92 g of ethanol (molar mass 46 g/mol). What is the mole fraction of ethanol in this mixture?
Select the correct option:
Solution
0.500
Mole fraction is defined as the ratio of the number of moles of a component to the total moles of all components in the mixture. Moles of water = 36/18 = 2.0 mol. Moles of ethanol = 92/46 = 2.0 mol. Total moles = 2.0 + 2.0 = 4.0 mol. Mole fraction of ethanol = 2.0 / 4.0 = 0.500. Option 0.667 would result if the student calculated 2/(2+1) = 0.667 using incorrect moles for one component. Option 0.333 is the mole fraction of water in a 1:2 water:ethanol mole ratio, not what is asked. Option 0.720 comes from incorrectly taking mass fractions instead of mole fractions — mass of ethanol / total mass = 92/128 = 0.719 ≈ 0.720. It is important to distinguish mole fraction from mass fraction; the former uses moles while the latter uses masses. This calculation appears directly in NCERT Chapter 2 and forms the basis for applying Raoult's law and other mixture calculations. Plausibility check: since both components have equal moles here, the mole fractions are equal (0.5 each), which correctly sums to 1.0.
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About This Question
- Subject
- chemistry
- Chapter
- solutions
- Topic
- mole fraction and mass fraction
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
0.500
Mole fraction is defined as the ratio of the number of moles of a component to the total moles of all components in the mixture. Moles of water = 36/18 = 2.0 mol. Moles of ethanol = 92/46 = 2.0 mol. Total moles = 2.0 + 2.0 = 4.0 mol. Mole fraction of ethanol = 2.0 / 4.0 = 0.500. Option 0.667 would result if the student calculated 2/(2+1) = 0.667 using incorrect moles for one component. Option 0.333 is the mole fraction of water in a 1:2 water:ethanol mole ratio, not what is asked. Option 0.720 comes from incorrectly taking mass fractions instead of mole fractions — mass of ethanol / total mass = 92/128 = 0.719 ≈ 0.720. It is important to distinguish mole fraction from mass fraction; the former uses moles while the latter uses masses. This calculation appears directly in NCERT Chapter 2 and forms the basis for applying Raoult's law and other mixture calculations. Plausibility check: since both components have equal moles here, the mole fractions are equal (0.5 each), which correctly sums to 1.0.
This easy difficulty chemistry question is from the chapter solutions, covering the topic of mole fraction and mass fraction. It appeared in the 2025 exam.
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