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Mole Concept And Avogadro's Number

Mediumchemistry

Calculate the number of molecules present in 9 g of water ((\text{H}_2\text{O})). ((N_A = 6.022 \times 10^{23}) mol(^{-1}), Molar mass of water = 18 g/mol)

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About This Question

Subject
chemistry
Chapter
some basic concepts in chemistry
Topic
mole concept and avogadro's number
Difficulty
Medium
Year
2025
Tags
Avogadro's numbernumber of moleculesmole conceptwaterparticle counting

Solution

Correct Answer:

\(3.011 \times 10^{23}\)

Avogadro's number specifies that one mole of any substance contains exactly (6.022 \times 10^{23}) entities. The number of molecules is found by first converting mass to moles, then multiplying by Avogadro's number. Moles of water (= 9/18 = 0.5) mol. Number of molecules (= 0.5 \times 6.022 \times 10^{23} = 3.011 \times 10^{23}). Option (1.806 \times 10^{23}) is incorrect; it would correspond to (0.3) mol, not 0.5 mol. Option (6.022 \times 10^{23}) is the number for a full mole (18 g), not 9 g. Option (1.204 \times 10^{24}) corresponds to 2 mol (36 g of water), which is twice the given mass. This question directly applies the NCERT concept linking mass, moles, and number of particles via Avogadro's number. Plausibility check: 9 g is exactly half of 18 g (one mole), so the answer must be exactly half of (N_A), giving (3.011 \times 10^{23}).

This medium difficulty chemistry question is from the chapter some basic concepts in chemistry, covering the topic of mole concept and avogadro's number. It appeared in the 2025 exam.

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