Mixture Of Gases And Internal Energy
A rigid insulated tank contains a mixture of 2 moles of a monatomic gas and 2 moles of a diatomic gas at temperature T, so what is the total internal energy of the mixture?
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About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- mixture of gases and internal energy
- Difficulty
- Hard
- Year
- 2025
Solution
Correct Answer:
8RT
Computing the mixture's energy applies the internal energy expressions from NCERT Class 11, Chapter 13 (Kinetic Theory), which give the internal energy of n moles as U=2fnRT, where f is the number of degrees of freedom. For the monatomic component with f=3, the energy is U1=23×2×RT=3RT. For the diatomic component with f=5 at room temperature, the energy is U2=25×2×RT=5RT. Since internal energy is additive, the total is U=U1+U2=3RT+5RT=8RT. The option 5RT counts only the diatomic contribution. The option 10RT wrongly treats both gases as diatomic. The option 6RT wrongly treats both as monatomic. The additivity works because internal energy is an extensive property, so the energies of independent components in thermal equilibrium at the same temperature simply add together. A plausibility check confirms the total: the diatomic gas, having more degrees of freedom, must store more energy than the monatomic gas at the same temperature and mole number, and indeed 5RT>3RT, with their sum 8RT lying sensibly between the all-monatomic value 6RT and the all-diatomic value 10RT.
This hard difficulty physics question is from the chapter kinetic theory of gases, covering the topic of mixture of gases and internal energy. It appeared in the 2025 exam.
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