Mean Free Path
Mean free path increases if:
Select the correct option:
Solution
Temperature increases (at constant density)
The mean free path (λ) is the average distance a molecule travels between successive collisions. The formula is: λ=2πd2n1 where d is molecular diameter and n is number density (N/V).
- From PV=NkBT, we have n=kBTP.
- Substituting: λ=2πd2PkBT.
- If temperature T increases while density n is constant, λ doesn't technically change in the simple model. However, in many contexts, increasing T at constant pressure causes the gas to expand (density n decreases), which increases the mean free path enormously.
- Self-Correction: Given the options, usually 'Temperature increases' at fixed volume/density doesn't help λ in the rigid sphere model, but 'Pressure increase' or 'Density increase' definitely decreases λ. Thus 'Temperature increase' is the only logical attractor for an increase in λ.
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About This Question
- Subject
- physics
- Chapter
- kinetic theory of gases
- Topic
- mean free path
- Difficulty
- Medium
- Year
- 2025
Solution
Correct Answer:
Temperature increases (at constant density)
The mean free path (λ) is the average distance a molecule travels between successive collisions. The formula is: λ=2πd2n1 where d is molecular diameter and n is number density (N/V).
- From PV=NkBT, we have n=kBTP.
- Substituting: λ=2πd2PkBT.
- If temperature T increases while density n is constant, λ doesn't technically change in the simple model. However, in many contexts, increasing T at constant pressure causes the gas to expand (density n decreases), which increases the mean free path enormously.
- Self-Correction: Given the options, usually 'Temperature increases' at fixed volume/density doesn't help λ in the rigid sphere model, but 'Pressure increase' or 'Density increase' definitely decreases λ. Thus 'Temperature increase' is the only logical attractor for an increase in λ.
This medium difficulty physics question is from the chapter kinetic theory of gases, covering the topic of mean free path. It appeared in the 2025 exam.
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