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Maximum And Minimum Of Roots

Hardmathematics

If the equation x^2 - (k - 3)x + k = 0 has both roots real, then the set of all real values of the parameter k satisfying this condition is which interval?

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About This Question

Subject
mathematics
Chapter
complex numbers and quadratic equations
Topic
maximum and minimum of roots
Difficulty
Hard
Year
2025
Tags
advanced-calculus-drilldiscriminant-conditionparametric-quadraticreal-rootssign-analysis

Solution

Correct Answer:

k ≤ 1 or k ≥ 9

Real roots of a quadratic require a non-negative discriminant, the primary JEE Advanced condition for parametric root problems. For x^2 - (k - 3)x + k = 0, the discriminant is D = (k - 3)^2 - 4k. Expanding gives k^2 - 6k + 9 - 4k = k^2 - 10k + 9. Requiring D ≥ 0 means k^2 - 10k + 9 ≥ 0, which factors as (k - 1)(k - 9) ≥ 0. This product is non-negative when k ≤ 1 or k ≥ 9, the regions outside the roots of the auxiliary quadratic. Option 1 ≤ k ≤ 9 selects where the discriminant is negative, giving complex roots. Option k ≥ 9 only drops the lower branch. Option all real k ignores the constraint entirely. Hence k ≤ 1 or k ≥ 9. Plausibility check: at the boundary k = 1, D = (1 - 9)(1 - 1)? compute D = 1 - 10 + 9 = 0, giving equal real roots, confirming the endpoints belong to the solution set. The argument of a difference ratio measuring the angle a segment subtends at a moving point is one of the most powerful locus tools in the Argand plane, producing circles, arcs and lines from clean angle conditions. The angle-in-a-semicircle theorem, here giving a right angle on a circle with the segment as diameter, is the geometric backbone that converts an algebraic argument equation into a recognizable curve.

This hard difficulty mathematics question is from the chapter complex numbers and quadratic equations, covering the topic of maximum and minimum of roots. It appeared in the 2025 exam.

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