Masses & Pulley (atwood)
In a light frictionless pulley system, masses 3 kg and 7 kg are released from rest. Acceleration of system (g = 10 m/s²)?
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About This Question
- Subject
- physics
- Chapter
- laws of motion
- Topic
- masses & pulley (atwood)
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
4 m/s²
- Basic Atwood Machine: Total unbalanced force is the difference in weights: (m2−m1)g.
- System Mass: Total mass being accelerated is (m1+m2).
- Formula: Using a=MtotalFnet:
- a=m1+m2(m2−m1)g
- Calculation:
- a=7+3(7−3)×10
- a=1040=4 m/s2.
- Direction: The 7 kg mass moves down, and the 3 kg mass moves up with this acceleration.
This easy difficulty physics question is from the chapter laws of motion, covering the topic of masses & pulley (atwood). It appeared in the 2025 exam.
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