Mass-spring Period
Easyphysics
Period of mass m on spring constant k?
Select the correct option:
Solution
Incorrect! Answer:
2π√(m/k)
- Angular Frequency ((\omega)): For a spring-mass system, ω=mk.
- Relating to Period (T): Period is the time taken for one full cycle: T=ω2π.
- Calculation:
- T=2π÷mk
- T=2πkm.
- Dependence: Increasing mass slows down the oscillation (longer T), while a stiffer spring (higher k) speeds it up (shorter T).
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About This Question
- Subject
- physics
- Chapter
- oscillations and waves
- Topic
- mass-spring period
- Difficulty
- Easy
- Year
- 2025
Solution
Correct Answer:
2π√(m/k)
- Angular Frequency ((\omega)): For a spring-mass system, ω=mk.
- Relating to Period (T): Period is the time taken for one full cycle: T=ω2π.
- Calculation:
- T=2π÷mk
- T=2πkm.
- Dependence: Increasing mass slows down the oscillation (longer T), while a stiffer spring (higher k) speeds it up (shorter T).
This easy difficulty physics question is from the chapter oscillations and waves, covering the topic of mass-spring period. It appeared in the 2025 exam.
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